• (2005?乌兰察布)如图,已知AC平分∠PAQ,点B,B′分别在边AP,AQ上.下列条件中不能推出AB=AB′的是( )试题及答案-单选题-云返教育

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      (2005?乌兰察布)如图,已知AC平分∠PAQ,点B,B′分别在边AP,AQ上.下列条件中不能推出AB=AB′的是(  )

      试题解答


      B
      解:如图:∵AC平分∠PAQ,点B,B′分别在边AP,AQ上,
      A:若BB′⊥AC,
      在△ABC与△AB′C中,∠BAC=∠B′AC,AC=AC,∠ACB=∠ACB′,
      ∴△ABC≌△AB′C,
      AB=AB′;
      B:若BC=B′C,不能证明△ABC≌△AB′C,即不能证明AB=AB′;
      C:若∠ACB=∠ACB′,则在△ABC与△AB'C中,∠BAC=∠B′AC,AC=AC,△ABC≌△AB′C,AB=AB′;
      D:若∠ABC=∠AB′C,则∠ACB=∠ACB′∠BAC=∠B′AC,AC=AC,△ABC≌△AB′C,AB=AB′.
      故选B.

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