• 已知log147=a,log145=b,则用a,b表示log3528= .试题及答案-填空题-云返教育

    • 试题详情

      已知log147=a,log145=b,则用a,b表示log3528=         

      试题解答


      2-a
      a+b

      解:∵log3528=
      log1428
      log1435
      =
      log14(14×
      14
      7
      )
      log145+log147
      =
      log14142-log147
      log145+log147
      =
      2-log147
      log145+log147

      ∵log
      147=a,log145=b∴原式=
      2-a
      a+b

      故答案为:
      2-a
      a+b
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